Find the Lem and the HCF of 15, 18, 45, by frime
fractiosation method
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Answered by
11
Answer:
We have ,
- 15 = 3¹×5¹
- 18 = 2×3×3 = 2¹×3²
- 45 = 3×3×5 = 3² × 5¹
- HCF(15,18,45) = 3¹= 3.
- /* Product of the smallest power of each common prime factors of the numbers*/
- HCF(15,18,45)= 3.......
hopes it helps you....
Answered by
10
Answer:
cha....
adi kuda raadaa...????
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