find the lenght of a diagonal of rectangule whose length is 8 cm and width is 6 cm
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Step-by-step explanation:
In rectangle ABCD,
If we construct a diagonal it will create a right - angled triangle
By the given condition,
In∆ADC
By Pythagoras theorem,
AD^2+DC^2= AC^2
6^2+8^2=AC^2
36+64=AC^2
100= AC^2
√100=AC .... ( taking sq.roots)
10=AC
therefore,
AC= 10cm
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