Question

Find the lenght of the chord A C where A B and C D are the t​

Answer 1

Answer:

Solution

In right triangles QAP and OCQ, we have

OA

2

=OP

2

+AP

2

and OC

2

=OQ

2

+CQ

2

∴r

2

=x

2

+(2.5)

Answer 2

Answer:

Correct option is

A

True

Given- AB&CD are chords of a circle and they are equidistant (4cm) from the centre O.

To find out- Whether AB=CD.

Solution-

OM and ON are perpendiculars=4cm from O to AB & CD, respectively.

∴ They bisect AB & CD

i.e AM=

2

1

AB & DN=

2

1

DC

∠OMA=∠OND=90

o

.

Now, between the ΔAOM & △DON we have, OM=ON=4cm ...(given),

∠OMA=∠OND=90

o

OA=OD ...(radii of the same circle).

∴ΔAOM≡ΔDON ...(RHS test).

∴AM=DN⟹AB=DC.

So, the statement is true.

please make brain list answer please