Question

Find the lenght of the chords which is 5cm away from the centre of a circle with radius 13 cm?​

Answer 1

it forms a triangle with perpendicular =5 and hypotenuse = 13

by Pythagoras theorem

H² =P²+B²

13² = 5² +B²

B² = 13² -5²

B² = 169-25

B² = 144

B= √144 = 12cm.

hence the length of chord is 12 ×2 = 24 cm

Answer 2

Answer:

12

Step-by-step explanation:

diagram is above

let center of the circle be O and the point wher chord inter sector be A,B and a point were line from center be C

A.T.Q

OC = 5cm (distance between center and chord)

OB = 13 cm (radii of circle)

in right angle triangle COB

hy² = b²+ p² (phythogores thoream)

OB²=CB²+ OC²

13² = CB² +5²

169 = CB²+25

169 -25 = CB²

√144 = CB

12 cm = CB

AB = AC+CB. (but AB = CB because OC divides chord in equal parts )

AB = 12 +12

AB = 24 cm ( chord)

/// I think it may help you ///