Question

find the lenght of the longest rod that can be placed in a room of dimension 10m×8m×6​

Answer 1

Answer:

Here is your solutions

Given :-

a room of dimension 10m × 8m×6m (dimensions in shape of cuboid )

To find length of the longest rod.

Diagonal of cuboid = longest rode

so we will find Diagonal of cuboid

\begin{gathered}d = \sqrt{l {}^{2} + h {}^{2} + b {}^{2} } \\ d = \sqrt{10 {}^{2} + 8 {}^{2} + 6 {}^{2} } \\ d = \sqrt{100 + 64 + 36} \\ d = \sqrt{200} \\ d = 10 \sqrt{2} \: m\end{gathered}d=l2+h2+b2d=102+82+62d=100+64+36d=200d=102m

Hope it helps you

Step-by-step explanation:

hope it helps u

Answer 2

The length of the longest rod that can be placed in a room is equal to the length of diagonal of the room

THE LENGTH OF THE DIAGONAL IS GIVEN BY:

$DIAGONAL \: of \: cuboid \: = \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} }$

Therefore length of longest rod that can be placed in the room = √(10²+8²+6²)

=√(100+64+36)

=√200

= 10√2 m

Therefore length of the longest rod that can be placed in the room is 10√2 m