Question

Find the lenght of the rectangle whose perimeter is 108cm and it's breadth is 20cm​

Answer 1

Answer:

44cm

Step-by-step explanation:

perimeter of rectangle= 2(l+b)

108 = 2(l+20)

108-20/2=l

l= 44cm

Answer 2

Answer :-

• The length of the rectangle = 34 cm.

Given :-

• Perimeter of the rectangle = 108 cm.
• Breadth of the rectangle = 20 cm.

To find :-

• The length of the rectangle.

Step-by-step explanation :-

• The question has given us the breadth and perimeter of the rectangle. We are asked to find its length. We will do so by using the formula required for finding the perimeter of the rectangle, make an equation using it and solve it to find the answer.

Calculations :-

We know that :-

$\underline{\fbox{Perimeter of a rectangle = 2 (L + B).}}$

So let's apply this formula.

Here,

Perimeter = 108 cm.

Breadth = 20 cm.

Let the length be l.

Substituting the given values in the formula :-

$\sf108 = 2 \: (l + 20)$

Removing the brackets,

$\sf108 = 2l + 40$

Transposing 40 from LHS to RHS, changing it's sign,

$\sf108 - 40 = 2l$

On simplifying,

$\sf68 = 2l$

Transposing 2 from RHS to LHS, changing it's sign,

$\sf \dfrac{68}{2} = l$

Dividing 68 by 2,

$\sf34 = l$

$\underline{\fbox{\sf l = 34.}}$

So, the length of the rectangle = 34 cm.