Find the lenghth of daigonal of rectangle whose side are 10cm and 8cm
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Diagonal divides the figure into two triangle...
Therefore, In triangle ABC
AB = 10cm
BC = 8cm
Thus, By Pythagoras Theorem,
AC² = AB² + BC²
= 10² + 8²
= 100 + 64
√AC² = √164
AC = 2√41 cm
Therefore, In triangle ABC
AB = 10cm
BC = 8cm
Thus, By Pythagoras Theorem,
AC² = AB² + BC²
= 10² + 8²
= 100 + 64
√AC² = √164
AC = 2√41 cm
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