Find the length AB in the triangle shown beside.if AD=18.
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Answered by
13
Answer:
Given, △ABC∼△DEF
Therefore,
DE
AB
=
EF
BC
=
FD
CA
So,
18
2x−1
=
3x+9
2x+2
=
6x
3x
Now taking
18
2x−1
=
6x
3x
, we have
18
2x−1
=
2
1
or 4x−2=18 or x=5
Therefore, AB=2×5−1=9,
BC=2×5+2=12,CA=3×5=15,
DE=18,EF=3×5+9=24
and FD=6×5=30
Hence,
AB=9cm,BC=12cm,CA=15cm,DE=18cm,EF=24cm and FD=30cm
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