Question

Find the length and area of a square whose perimeter is 48 cm.

Answer 1

$perimeter \: of \: square = {4a}^{2} \\ perimeter \: of \: square = 48 {cm}^{2} \\ length \: of \: square = \frac{48}{4} = 12cm \\ now. \: area \: of \: square = {s}^{2} \\ = 12 \times 12 = 144 {cm}^{2}$

Answer 2

perimeter of square=4a=48cm
=a=12cm
area of square=a2
=area=144cm2