Find the length and breadth
of a rectangle whose area is 25a^2-35a+12
Answers
Answered by
10
Hello Dear!!!
Here's your answer...
(5a-3) and (5a-4) are the factors of 25a^2-35a+12
25a^2 - 35a + 12
25a^2 -15a -20a +12
5a(5a-3) - 4(5a-3)
(5a-3) (5a-4)
Length is 5a - 3
Breadth is 5a - 4
_________________________________
Hope this helps you...
Here's your answer...
(5a-3) and (5a-4) are the factors of 25a^2-35a+12
25a^2 - 35a + 12
25a^2 -15a -20a +12
5a(5a-3) - 4(5a-3)
(5a-3) (5a-4)
Length is 5a - 3
Breadth is 5a - 4
_________________________________
Hope this helps you...
Cheenubird1234:
Yea
Answered by
13
Given Area:
25a²-35a+12
To Find :
Length and Breadth
Solution :
Factorising 25a²-35a+12
[By mid term spilting]
25a²-20a-15a+12
5a(5a-4)-3(5a-4)
(5a-4)(5a-3)
Length = 5a-4
Breadth = 5a-3
25a²-35a+12
To Find :
Length and Breadth
Solution :
Factorising 25a²-35a+12
[By mid term spilting]
25a²-20a-15a+12
5a(5a-4)-3(5a-4)
(5a-4)(5a-3)
Length = 5a-4
Breadth = 5a-3
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