Math, asked by Aditya7Pratap, 4 months ago

Find the length and breadth of a rectangle whose length is 4m more than four times its breadth and its
perimeter is 60m.

Answers

Answered by Flaunt
19

Given

Perimeter of Rectangle is 60m

length is 4m more than four times it's breadth

To Find

length and breadth of the Rectangle

\sf\huge\bold{\underline{\underline{{Solution}}}}

Let us assume the breadth of Rectangle be 'x'

according to the question

length would be => 4m+4x

Perimeter is 60m

Perimeter of Rectangle=2(length+Breadth)

=>60= 2( 4+4x +x)

=>60=2(4+5x)

=>2(4+5x)=60

=>4+5x=30

=>5x= 30-4

=>5x= 26

=>x= 26÷ 5

=>x=5.2

Now , breadth is 5.2m

length = 4+4x=4+4×5.2

length= 4+20.8=24.8m

Check

Perimeter of Rectangle=2( 24.8+5.2)

Perimeter of Rectangle=2(30)

Perimeter of Rectangle= 60m

Extra information=>

Perimeter is the total distance occupy by a solid 2D figure around its edge.

Area of Rectangle= length × breadth

Answered by Anonymous
1

Given

Perimeter of Rectangle is 60m

length is 4m more than four times it's breadth

To findi

length and breadth of the Rectangle

Slove

Let us assume the breadth of Rectangle be 'x'

according to the question

length would be => 4m+4x

Perimeter is 60m

Perimeter of Rectangle=2(length+Breadth)

=>60= 2( 4+4x +x)

=>60=2(4+5x)

=>2(4+5x)=60

=>4+5x=30

=>5x= 30-4

=>5x= 26

=>x= 26÷ 5

=>x=5.2

Now , breadth is 5.2m

length = 4+4x=4+4×5.2

length= 4+20.8=24.8m

Check

Perimeter of Rectangle=2( 24.8+5.2)

Perimeter of Rectangle=2(30)

Perimeter of Rectangle= 60m

Extra information=>

Perimeter is the total distance occupy by a solid 2D figure around its edge.

Area of Rectangle= length × breadth

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