Question

find the length and breadth of rectangle having breadth x+yand 3x-2y and length x+7 and x+8
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Answer 1

Step-by-step explanation:

length = 15 units and breadth = 12.5 units

Step-by-step explanation:

I think these are the dimensions of sides as shown in the attachment.

So, we know that rectangle has length and breadth

i.e.

\begin{gathered}x + 7 = 3x - 2y \\ \\ x - 3x + 2y = - 7 \\ \\ - 2x + 2y = - 7 \\ \\ 2x - 2y = 7...eq1 \\ \\ \end{gathered}

x+7=3x−2y

x−3x+2y=−7

−2x+2y=−7

2x−2y=7...eq1

and

\begin{gathered}x + y = y + 8 \\ \\ x + y - y = 8 \\ \\ x = 8 \\ \\ \end{gathered}

x+y=y+8

x+y−y=8

x=8

So,

\begin{gathered}2(8) - 2y = 7 \\ \\ - 2y = 7 - 16 \\ \\ 2y = 9 \\ \\ y = 4.5 \\ \\ \end{gathered}

2(8)−2y=7

−2y=7−16

2y=9

y=4.5

Now, length of rectangle is

\begin{gathered}x + 7 \\ \\ = 8 + 7 = 15 \: unit \\ \\ 3x - 2y = 24 - 9 = 15 \: unit \\ \\ \end{gathered}

x+7

=8+7=15unit

3x−2y=24−9=15unit

Breadth

\begin{gathered}x + y = 8 + 4.5 = 12.5 \\ \\ y + 8 = 4.5 + 8 = 12.5 \: units \\ \\ \end{gathered}

x+y=8+4.5=12.5

y+8=4.5+8=12.5units

Hope it helps you.

Answer 2

Answer:

l=15units and b=12.5units