Question

find the length and breadth of the rectangel 5x+4, x-4 parimeter is 72m

Answer 1

Use can refer from here.

Answer 2

Given,  
              length of rect.     =     $5x+4m$
              breadth of rect.   =     $x-4m$

We know,            (the formula of perimeter)
            $2(l+b)=p$

(finding the value of x through solving an equation formed)

So,    $2(5x+4m+x-4m)=72m$

⇒      $5x+4m+x-4m= \frac{72m}{2} =36m$
⇒      $(5x+x)+(4m-4m)=36m$
⇒      $6x=36m$
⇒      $x= \frac{36m}{6}$
⇒      $x=6m$       

Therefore,
         
(the value of x has been inserted in the place of the varable x)

          ∴     Length of rectangle =   5x + 4m
                                                 =     $5(6m)+4$
                                                 =     $30m+4m$    
                                                 =     $34m$       (ans.)

          ∴    Breadth of rectangle =  x - 4m
                                                 =  $6m-4m$
                                                 =  $2m$       (ans.)

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