Find the length and breadth of the rectangle given below as length is given as 5x+4 and breadth as x-4 if it's perimeter is 72m
Answers
Answered by
419
perimeter of rectangle = 2 (L+B)
72 =2 (5X+4+X-4)
72 =2 (6X)
72/2=6X
36/6=X
6=X
length =5X+4
=5×6+4
=30+4
=34cm
breadth=X-4
=6-4
=2cm
72 =2 (5X+4+X-4)
72 =2 (6X)
72/2=6X
36/6=X
6=X
length =5X+4
=5×6+4
=30+4
=34cm
breadth=X-4
=6-4
=2cm
Answered by
140
Hi ,
Dimensions of the rectangle ,
Length = l = 5x + 4
Breadth = b = x - 4
According to the problem given ,
Perimeter = 72 m
2( l + b ) = 72
l + b = 72 /2
l + b = 36
5x + 4 + x - 4 = 36
6x = 36
x = 36 / 6
x = 6
l = 5x + 4 = ( 5 × 6 ) + 4 = 30 + 4
l = 34 m
b = x - 4
b = 6 - 4
b = 4 m
Therefore ,
l = 34m , b = 4m
I hope this helps you.
:)
Dimensions of the rectangle ,
Length = l = 5x + 4
Breadth = b = x - 4
According to the problem given ,
Perimeter = 72 m
2( l + b ) = 72
l + b = 72 /2
l + b = 36
5x + 4 + x - 4 = 36
6x = 36
x = 36 / 6
x = 6
l = 5x + 4 = ( 5 × 6 ) + 4 = 30 + 4
l = 34 m
b = x - 4
b = 6 - 4
b = 4 m
Therefore ,
l = 34m , b = 4m
I hope this helps you.
:)
kumarmangalam:
Sir. ....6-4 always gives 2 only
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