Question

find the length and breadth of the rectangle whose perimeter is 128meter the length and breadth are in the rato of 3:1​

Answer 1

$\mathfrak{\huge{\underline{Answer:}}}$

Let Length Be 3x and Breadth be x

Given Perimeter = 128 m

$\textbf{\underline{\underline{According\:To\:Question :}}}$

$\sf \: Perimeter = 2(l + b)$

$\sf \: 128m = 2(3x + x)$

$\sf \: 128 = 2\times 4x$

$\sf \: 128 = 8x$

$\sf \: x = \dfrac{128}{8}$

$\underline{\underline{x=16\:m}}$

As We Took Breadth as x then Breadth = 16 m

And Length = 16×3 = 48m

$\mathfrak{\huge{\underline{Verification:}}}$

Perimeter = 2(l+b)

128 m = 2(48+16)

128 m = 96 + 32

128 m = 128 m

Answer 2

AnswEr :

Length = 48 m

Breadth = 16 m

Explanation :

⋆ Perimeter of Rectangle is 128m.

⋆ Length and Breadth of Rectangle are in Ratio 3:1.

• Let the length and breadth be 3x and x respectively.

• According to Question Now :

⇒ Perimeter of Rectangle = 2 × (L + B)

• Plugging the Values

⇒ 128m = 2 × ( 3x + x )

⇒ 128m = 2 × 4x

⇒ 128m = 8x

⇒ 128m / 8 = x

⇒ x = 16m

◑ Length = 3x = (3 × 16) = 48m

◑ Breadth = x = 16m

჻ Length and Breadth of Rectangle is 48m and 16m respectively.