find the length and breadth whose perimeter is 40 centimetre and area is 100 square CM
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Step-by-step explanation:
Let the length of rectangle be x and breadth be y
as we know that
perimeter of rectangle =2 (length + breadth )
40=2 (x+y)
x+y=20
y=20-x
area of rectangle =length ×breadth
100=xy
x (20-x)=100
20x-x^2=100
x^2-20x+100=0
(x-10)^2=0
x=10cm
y=10cm
so length and breadth are equal .which is 10 cm each
Answered by
0
Answer:
perimeter of rectangle =2 (length + breadth )
40=2 (x+y)
x+y=20
y=20-x
area of rectangle =length ×breadth
100=xy
x (20-x)=100
20x-x^2=100
x^2-20x+100=0
(x-10)^2=0
x=10cm
y=10cm
so length and breadth are equal .which is 10 cm each
Step-by-step explanation:
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