Question

Find the length and perimeter of a rectangle of area 900 m2 and breadth 20 m.
Find the breadth and perimeter of a rectangle of area 962 cm2 and length 26 cm.
2
the side of a square of area (1) 1936 m (11) 900 cm (iii) 62 500 m2 (iv) 7.29 m2
2
24​

Answer 1

Answer:

Step-by-step explanation:

Given:-  1)

Breadth of the rectangle = 20m

Area of the rectangle = 900m^2

To find:-

Length of the rectangle

Perimeter of the rectangle

Solution:-

As we know,

Area of a rectangle = Length * Breadth

900 m^2 = Length * 20 m

=> 900m^2/20m = Length

=> 45m = Length

Now,

Perimeter of a rectangle = 2(Length +Breadth)

= 2(45m + 20m)

= 2(65m)

= 130 m)

2) Breadth=37. perimeter=126.

area=962

length=26

hence, area=L×B

962=26×B

B=962÷26

B=37

perimeter=2(L+B)

=2(26+37)

=126

3) 1. 1936=a²

√1936=a

44 = a

2. 900=a²

√900=a

30= a

3. 62500=a²

√62500=a

250=a

4. 7.29=a²

√7.29=a

2.7=a