Question

Find the length and width of a rectangle whose perimeter is 32 feet and whose area is 60 square feet. find the length of the longer and the width of the shorter side.

Answer 1

Step-by-step explanation:

p = 34 = 2w+2l

a = 60 = wl; l = 60/w

...

2w + 2(60/w) = 34

2w + 120/w = 34

2w^2 + 120 = 34w

2w^2 - 34w + 120 = 0

(2w-10)(w-12)

w = 10/2 = 5

w = 12

...

lenth and width are 5ft and 12ft

...

Check

5*12 = 60

2(5) + 2(12) = 10 + 24 = 34

Answer 2

See the above attachment for answer.