Question

Find the length of 10 m wide room whose perimeter is 44 m.

Answer 1

$let\: length \: of \: the \: room = l \\ \\ given \: breadth \: of \: the \: room = b = 10m \\ \\ since \: room \: is \: in \: the \: rectangular \: shape \\ \\ therefore \: perimeter \: of \: the \: room \: \\ = 2(l + b) \\ \\ therefore \: according \: to \: question \\ \\ 2(l + 10) = 44 \\ \\ = > l + 10 = \frac{44}{2} \\ \\ = > l = 22 - 10 \\ \\ = > l = 12 \: m$
Therefore length of the room is 12 m.

hope it helps

Answer 2

Hey Mate,

Given,

Width = 10 m

Perimeter = 44 m

Perimeter of the Rectangle = 2 ( Length + Width )

=> 44 m = 2 ( Length + 10 m )

=> 44 m = 2 Length + 20 m

=> 44 m - 20 m = 2 Length

=> 24 m = 2 Length

=> 24 m / 2 = Length

=> Length = 12 m

Therefore, the length is 12 m.

Hope it Helps!