Find the length of a chord which at a distance of 3 cm from thr center of circlr of radius 5 cm......
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Answer:
OA be radius = 5cm
OB the distance between the Chord and Centre = 3cm
We have to find AB
In ∆ABO, /_B = 90°
(A line from centre is perpendicular to Chord)
OA² = OB² + AB²
5² = 3² + AB²
AB² = 25 - 9
AB² = 16
AB = 4 cm
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