Question

find the length of a chord which is at a distance of 21 cm from the centre of the circle of radius 29 CM​

Answer 1

Answer:

since r = 29 cm

d = 21 cm

length of chord = 2 (21square + 29 square)

2 × ( 441 + 841)

2 × 1282 = 2564cm answer

Answer 2

Answer:

40 cm

Step-by-step explanation:

r=29cm

distance= 21 cm which is also the chord bisector

The chord is twice its base

h²=b²+p²

(29cm)²= b²+(21cm)²

b²= (29cm)²-(21cm)²

b²= (29cm+21cm)(29cm-21cm)

b²= 50cm×8cm

b=√400cm²

=20cm

So the chord is twice the base= 20cm×2= 40cm

Hope it helps!