Question

find the length of a chord which is at a distance of 3cm from the centre of the circle of radius 5cm

Answer 1

By pythogoras theoram,
let AB be the chord of the circle
P is the mid point of the chord
OP=3cm
OB=5cm


PB×PB=OB×OB-OP×OP
=5×5-3×3
=25-9
=16
PB×PB =4×4
PB=4CM
THEN,AB=2(PB)
=2×4=8
then chord of the circle will be 8 cm

Answer 2

Answer:

Given that :-

Radius of the Circle, (r) = 5 cm

Distance of the chord from the centre = 3 cm

To Find:-

Length of the chord

Formula to be used :-

Pythagoras theorem

Solution:-

Let AOC is a right angled triangle.

By Using Pythagoras theorem, we get

⇒ AO² + OC² = AC²

⇒ 3² + OC² = 5²

⇒ 9 + OC² = 25

⇒ OC² = 25 - 9

⇒ OC² = 16

⇒ OC = 4

Length of the chord = 4 + 4 = 8 cm.

Hence, the length of the chord is 8 cm.