Find the length of a chord which is at a distance of 4 cm from the centre of a circle of radius 6 cm.
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Answer:
Radius of circle (OA)= 6cm
Distant (OC)=4cm
In Δ OCA by Pythagoras theorem
AC2+OC2=OA2
⇒
AC2+42=62
⇒
AC2=36-16
⇒AC=20=4.47cm
WKT, the perpendicular distance from center to chord bisects the chord.
AC=BC=4.47cm
Then, AB=4.47+4.47
8.94 cm
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