Find the length of a chord which is at a distance of 5 cm from the center of a circle of radius 12 cm
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Step-by-step explanation:
AM2 = 169 - 144 = 25 ⇒ AM = 5cm. As the perpendicular from the centre of a chord bisects the chord. Therefore, AB = 2AM = 2 x 5 = 10cm.
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Answer:
√{12^2-5^2}=√{144-25}=√119
Ans=2×√119
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