Find the length of a chord which is at a distance of 5 cm from the center of a circle of radius 12 cm
Answers
Answered by
0
Step-by-step explanation:
AM2 = 169 - 144 = 25 ⇒ AM = 5cm. As the perpendicular from the centre of a chord bisects the chord. Therefore, AB = 2AM = 2 x 5 = 10cm.
Answered by
1
Answer:
√{12^2-5^2}=√{144-25}=√119
Ans=2×√119
Similar questions
Math,
15 days ago
Social Sciences,
15 days ago
Computer Science,
15 days ago
Math,
1 month ago
Physics,
1 month ago
English,
8 months ago
English,
8 months ago
Math,
8 months ago