Question

find the length of a chord which is at a distance of 5cm from the centre of a circle of radius 13 cm​

Answer 1

Answer:

answer is 12

Explanation:

169=25+x2

169-25=x2

x2=144

x=12

Answer 2

Explanation:

Let AB be the chord of a circle of radius 13 cm at a distance of 5cm from centre O.

Then, OA=13xm, OM=5cm

Using Pythagoras theorem,

OA²=OM²+AM²

i.e.,.

${13}^{2} = {5}^{2} + {am}^{2}$

or

${AM}^{2} = {13}^{2} - {5}^{2}$

$= 169 - 25 = 144$

$AM = 12$

$AB = 2 \times 12 = 24cm$

perpendicular perpendicular from centre bisector of chord

length of the chord = 24 cm