Find the length of a chord which is at a distance of 8 cm from the centre of a circle of radius 17 cm.
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30cm........ ............
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★ Find the length of a chord which is at a distance of 8 cm from the centre of a circle of radius 17 cm.
★30 cm
Let AB be a chord of a circle with centre O and radius 17 cm.
Draw OL ⊥ AB. Join OA.
Then, OL = 8 cm and OA = 17 cm
From the right △OLA, we have
OA² = OL² + AL²
==> AL² = OA² – OL² = [(17)² – (8)²] cm²
= (17+8)(17–8) cm²
==> AL² = √225cm = 15cm
Since the perpendicular from the centre of a circle to a chord bisects the chord, we have
AB = 2 × AL = (2×15) cm = 30 cm
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