find the length of a chord which is at a distance of 8 cm from the center of a circle of radius 17 cm.
200t:
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Answer:
Step-by-step explanation:
given circle with centre o
let 'ab' be the chord
r=17cm
distance=8cm
now by pgt
ao2=om2+am2
[17]sq=8sq+am2
289-64=am2
225=am2
am=√225
am=√15sq
am=15cm
now length of chord twice of am {as am is perpendicular to chord so it has divided it into two equal parts]
2*15=30cm
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