find the length of a diagonal of a quadrilateral whose area is 195msquare and the lengths of the perpendiculars to the diagonal from opposite vertics are 8.5m and 11m respectively
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AC = 20 m
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The length of the diagonal is 20 m.
- Given the diagonal is AC and the perpendicular from B to AC intersects at M and the perpendicular from D to AC intersects at N.
- Now it is given that Area of quadrilateral ABCD is 195 sq. m
- The lengths of the perpendicular from opposite vertices of the diagonal to the diagonal is given as 8.5m and 11m.
- Let say, BM = 8.5 m and DN = 11 m.
- Now we write ,
- Area of quadrilateral ABCD = Area of triangle ABC + Area of triangle ADC
Area of quadrilateral ABCD = (1/2)×AC×BM + (1/2)×AC×DN
195 = (1/2)×AC×BM + (1/2)×AC×DN
195×2 = AC×BM + AC×DN
195×2 = AC×8.5 + AC×11
390 = AC (8.5 + 11)
390 = AC (19.5)
AC = 20 m
- The length of the diagonal is 20 m.
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