Question

Find the length of a diagonal of a rectangular box of length 12 cm, width 5 cm and height 4 cm

Answer 1

length of Diagnol is

$\sqrt{ {12}^{2} + {5}^{2} + {4}^{2} }$

=>length will be

$\sqrt{184}$

is ur answer. Hope it helps u

Answer 2

The length of a diagonal of a rectangular box is about 13.60 cm.

Step-by-step explanation:

Length of a diagonal of a cuboid is

$Diagonal=\sqrt{l^2+b^2+h^2}$

where, l is length, b is breadth and h is height.

Length of box is 12 cm, width is 5 cm and height is 4 cm.

Substitute l=12, b=5, h=4 in the above formula.

$Diagonal=\sqrt{12^2+5^2+4^2}$

$Diagonal=\sqrt{144+25+16}$

$Diagonal=\sqrt{185}$

$Diagonal\approx 13.60$

The length of a diagonal of a rectangular box is about 13.60 cm.

#Learn more

If for a cuboid l^2+b^2+h^2=484cm^2 find the length of its diagonal.

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