Question

Find the length of a ladder kept at a distance of 12 m from the foot of a wall just reaches a
wide than along two of its adjacent sides?
window at a height of 5 m.
help me please​

Answer 1

Correct Question :-

• Find the length of a ladder kept at a distance of 12 m from the foot of a wall just reaches a window at a height of 5 m wide than along two of its adjacent sides?

To Find :-

• Length of the Ladder

Solution :-

It is given that the ladder is placed 12m front from the wall, So 12m is the Base and it reaches the window at a height of 5m , So 5m is the Perpendicular , Now we have to find the length of the Ladder which is nothing but Hypothenuse. For finding the Hypotenuse we will use Pythagoras Theorem I.e (Hypothenuse)² = (Perpendicular)² + (Base)²

${:} \longrightarrow \sf{\bf{(Hypothenuse)^{2}\: = \: (Perpendicular)^{2} \: + \: (Base)^{2} }} \\ \\ {:}\longrightarrow\sf{\sf{(Hypothenuse)^{2}\: = \: (12)^{2} \: + \: (5)^{2} }} \\ \\ {:} \longrightarrow\sf{\sf{(Hypothenuse)^{2}\: = \: 144 \: + \:25 }} \\ \\ {:}\longrightarrow\sf{\sf{(Hypothenuse)^{2}\: = \: 169 }} \\ \\ {:}\longrightarrow\sf{\sf{Hypothenuse\: = \: \sqrt{169} }} \\ \\ {:}\longrightarrow\sf \boxed{\sf{Hypothenuse\: = \: 13m}}$

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Therefore, Length of the Ladder is 13m

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Answer 2

Answer:

13 m

Step by step:

Hypotenuse²=Base²+Altitude ²

${12}^{2} + {5}^{2} \\ 144 + 25 \\ \sqrt{169 } \\ 13cm {}^{2}$