find the length of a lane 5 m wide which can be covered by 50000 bricks of size 22 cm by 15 cm
Answers
Answered by
96
Heya friend,
Here is your answer,
Width= 5 m (given)
No of bricks= 50,000 (given)
Area of per bricks = 22cm × 15cm = 330 cm² (given)
=> Area of 50,000 bricks = 500000 × 330 cm² = 16500000 cm²
=> 16500000 cm² = 1650 m²
So, the area of lane = 1650 m2
Now, since
=> Width = 5 m
=> Length = area/width
=> Length of lane = 1650 m²/ 5 m = 330 m
Thus,
The length of the lane = 330 m (ans)
Hope it helps you.
Thank you.
Here is your answer,
Width= 5 m (given)
No of bricks= 50,000 (given)
Area of per bricks = 22cm × 15cm = 330 cm² (given)
=> Area of 50,000 bricks = 500000 × 330 cm² = 16500000 cm²
=> 16500000 cm² = 1650 m²
So, the area of lane = 1650 m2
Now, since
=> Width = 5 m
=> Length = area/width
=> Length of lane = 1650 m²/ 5 m = 330 m
Thus,
The length of the lane = 330 m (ans)
Hope it helps you.
Thank you.
Answered by
44
hey....!
here's ur answer....!
area of the lane=area of 50000bricks
given length of the brick is 22cm and breadth is 15cm.
area of one brick=l×b
=22×15
=330cm²
therefore area of 50000bricks=50000×330
=16500000cm²
in metres=16500000/100×100
=165000m²
hence the area of the lane is also 1650m²
if width of the lane is 5m then length is:-
l×b=1650m²
l×5=1650m²
l=1650/5
l=330m
verification:-
area of lane=l×b
=330×5
=1650m²
hence verified.
thus, the length of the lane is 330m
hope this helps...!
(^^)
here's ur answer....!
area of the lane=area of 50000bricks
given length of the brick is 22cm and breadth is 15cm.
area of one brick=l×b
=22×15
=330cm²
therefore area of 50000bricks=50000×330
=16500000cm²
in metres=16500000/100×100
=165000m²
hence the area of the lane is also 1650m²
if width of the lane is 5m then length is:-
l×b=1650m²
l×5=1650m²
l=1650/5
l=330m
verification:-
area of lane=l×b
=330×5
=1650m²
hence verified.
thus, the length of the lane is 330m
hope this helps...!
(^^)
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