Question

find the length of a rectangle given that its perimeter is 880 and breadth is 88 metre​

Answer 1

$\large{\mathtt{\underbrace{\red{✠\:Required\:Answer\:✠}}}}$

Let it's length be 'x'

Breadth = 88m

Perimeter = 880m

$\huge{\boxed{\color{lime}{Perimeter\:=\:2(L+B)}}}$

Substituting the value, we get :-

880m = 2(x+88)

880m = 2x + 176m

880 - 176 = 2x

704 = 2x

x = $\dfrac{704}{2}$

x = 352 m

Answer 2

Perimeter of rectangle = 2(l+b)
880 = 2(L+88) perimeter = 880 and breadth = 88
880 = 2L+ 176
880-176 = 2L
704= 2L
704/2= L
352=L