Question

Find the length of a rectangle given that its perimeter is 880 m and breadth is 88m

Answer 1

Answer:

perimeter=2(lxb)

so,

given perimeter is 880

and breadth is 88

finding length

then

880=2(lx88)

880/2=(lx88)

440=lx88

l=440-88

l=352

ANS. length of rectangle is 352

Follow

me nd like

Answer 2

$\sf{\huge{\underline{\red{Given :-}}}}$

• The perimeter of rectangle is 880 m.

• The breadth of rectangle is 88m.

$\sf{\huge{\underline{\green{To\:Find :-}}}}$

• The length of a rectangle.

$\sf{\huge{\underline{\blue{Solution :-}}}}$

We know,

The Perimeter of Rectangle =2(Length + Breadth)

The perimeter of rectangle is 880 m. (Given)

➝ 880 = 2(Length + Breadth)

Let the length be x,

The breadth of rectangle is 88m.

➝ 880 = 2( x + 88)

➝ 880 = 2x + 176

➝ 2x = 880 - 176

➝ 2x = 704

➝ x = $\cancel{\dfrac{704}{2}}$

➝ x = 352

Hence , The length of a rectangle 352m .

_____________________________________

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large x cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 88 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$