Question

Find the length of a rectangle if the perimeter and width are:

perimeter =102 cm, width = 16 cm​

Answer 1

Question:-

Find the length of a rectangle if the perimeter and width are:

perimeter =102 cm, width = 16 cm

Answer:-

• The length of Rectangle is 35 cm.

To find:-

• length of Rectangle

Solution:-

• Perimeter of rectangle = 102 cm
• Breadth of rectangle = 16 cm

We have to find length of Rectangle.

As we know,

$\large{ \boxed{ \mathfrak{ perimeter = 2(l + b)}}}$

Where,

• l = length of Rectangle
• b = breadth of rectangle

Put the values in the formula

According to question,

$\large{ \bf : \implies \: \: \: \: 2(l + 16) = 102}$

$\large{ \bf : \implies \: \: \: \: l + 16 = \frac{102}{2} }$

$\large{ \bf : \implies \: \: \: \: l + 16 = 51}$

$\large{ \bf : \implies \: \: \: \: l = 51 - 16}$

$\large{ \bf : \implies \: \: \: \: l = 35}$

Hence,

The length of Rectangle is 35 cm.

Answer 2

☆ Solution ☆

Given :-

• Perimeter = 102 cm
• Width = 16 cm

To Find :-

• The length of a rectangle.

Step-by-Step-Explaination :-

As we know that :-

Perimeter of rectangle = 2 ( l + b )

Putting the respective value,

=> 2 ( l + 16 ) = 102

=> l + 16 = 102/2

=> l + 16 = 51

=> l = 51 - 16

=> l = 35

Hence,

The length of Rectangle is 35 cm.

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☆ Additional Information ☆

Perimeter of Rectangle = 2 ( l + b )

Area of Rectangle = L × B

Perimeter of square = 4 × side

Area of Square = ( side ) ²

Perimeter of Rhombus = 4 × sides

Area of Rhombus = Product of Diagonal/2.

Perimeter of Parallelogram = 2 ( a + b )

Area of Parallelogram = Base × Height

Perimeter of Triangle = a + b + c

Area of Triangle = 1/2 × base × height

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