Question

find the length of a rectangle whose area is 20x^3y2-15x^2y^2+10xy^2+5xy and breadth is 5xy

Answer 1

Step-by-step explanation:

Area(A) = length(l) × breadth(b)

Given,

A = 20x³y²-15x²y²+10xy²+5xy

b = 5xy

Now,

l = A/b

= (20x³y²-15x²y²+10xy²+5xy)/5xy

=5xy(4x²y - 3xy + 2y +1 )/5xy

= 4x²y - 3xy + 2y +1

The length of the rectangle is : (4x²y - 3xy + 2y +1)

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