Question

Find the length of a rectangle whose area is 54 sq . m and breadth is 9m.
​

Answer 1

Area of rectangle is length multiplied by width that is

A=l×w

Now substitute l=9 and A=54, we get

54=9×w

⇒w=

9

54

⇒w=6 cm

Perimeter of rectangle is P=2l+2b that is

P=2(9)+2(6)

=18+12

=30cm

Answer 2

Answer:

In a rectangle,

breadth=9m

Area=54 sq.m

ATQ,

area=length*breadth

54=length*9

=)length*9=54

=)length=54/9

=)9

Step-by-step explanation:

hope it helps..........

mark as brainliest........

plz follow me.......