Question

Find the length of a rectangle whose area is 80 sq.cm and breadth is 8 CM​

Answer 1

$\frak{Given}\begin{cases}\sf{\;\;\; Breadth_{\: rectangle)} = 8 \; cm}\\\sf{\;\;\; Area_{\:(rectangle)} = 80\; cm^2}\end{cases}$

Need to find: Length of the rectangle.

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$\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}$⠀⠀⠀⠀

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$\star\;\boxed{\sf{\pink{Area_{\:(rectangle)} = Length \times Breadth}}}$

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• We've given area of the rectangle is 80 cm².

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Therefore,

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$:\implies\sf Length \times Breadth = 80 \\\\\\:\implies\sf Length \times 8 = 80 \\\\\\:\implies\sf Length = \cancel\dfrac{80}{8} \\\\\\:\implies{\underline{\boxed{\frak{\purple{Length_{\:(rectangle)} = 10\;cm}}}}}\;\bigstar$

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$\therefore{\underline{\sf{Hence, \: Length \; of \: the \; rectangle \: is\; \bf{10\:cm }.}}}$

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$\qquad\quad\boxed{\bf{\mid{\overline{\underline{\bigstar\: More \ to \ know\: :}}}}\mid}$⠀

• A Quadrilateral with four sides is called as rectangle. And, opposite sides of a rectangle are parallel and are equal in length.

• Perimeter of Rectangle = 2(Length + Breadth)

• Area of a Rectangle Formula,  A = Length × Breadth

• Diagonal of a Rectangle Formula is, $\sf D = \sqrt{(l)^2 + (b)^2}$

Answer 2

Given:

↪Area of rectangle: 80cm²

↪Breadth: 8cm

To Find:

↪Length of the rectangle

Solution:

Let the length of the rectangle be l.

We know that,

Area of rectangle = l × b

80cm² = l × 8

l = 80/8

l = 10cm

Hence, the length of the rectangle is 10cm.