Question

find the length of a rectangle whose breadth is 5 cm and area is 75 sq CM​

Answer 1

Answer:

b= 5cm

area=75cm²

l=?

therefore area of a rectangle = l×b

75cm² = l× 5

75\5 = l

25cm = l

length = 25cm

Answer 2

$\huge \fbox{Answer}$

$\large \underline{\underline {\frak {\color{red}Given::}}}$

$\mapsto \sf{Breadth \: of \: rectangle=5cm}$

$\sf \mapsto{Area \: of \: rectangle=75 {cm}^{2} }$

$\large \underline{\underline {\frak {\color{blue}To \: find::}}}$

$\leadsto \sf{Length \: of \: rectangle.}$

$\large \underline{\underline {\frak {\color{indigo}Formula \: required::}}}$

$\star{ \boxed{\rm{Length \: of \: rectangle = \frac{Area \: of \: rectangle}{Breadth \: of \: rectangle} }}} \star$

$\large \underline{\underline {\frak {\color{i}According \: to \: Question::}}}$

${{ \implies{\sf{Length \: of \: rectangle = \frac{Area \: of \: rectangle}{Breadth \: of \: rectangle} }}}}$

${{ \implies{\sf{Length \: of \: rectangle = \frac{75 {cm}^{2} }{5cm} }}}}$

${{ \implies{\sf{Length \: of \: rectangle = 15cm}}}}$

$\large \underline{\underline {\frak {{ \pink{Know \: more::}}}}}$

$\boxed{ \begin{array}{ |c|c| } \hline \sf Area \: of \: rectangle & \sf length(l) \times breadth(b) \\ \hline \sf Perimeter \: of \: rectangle& \sf2(length + breadth) \\ \hline \sf Length \: of \: rectangle& \sf \frac{Area \: of \: rectangle}{Breadth \: of \: rectangle} \\ \hline \sf Breadth \: of \: rectangle & \sf\frac{Area \: of \: rectangle}{Length \: of \: rectangle} \\ \hline \sf Diagonal \: of \: rectangle & \sf \sqrt{ {(length)}^{2} + {(breadth)}^{2} } \\ \end{array}}$

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