Question

Find the length of a room whose area is 153÷10sq.m and whose breadth is 2 11÷20m​

Answer 1

Answer:

Length of room is 6 m.

Step-by-step explanation:

Given:

Area of room = $\frac{153}{10}\:m^2$

Breadth of room = $2\frac{11}{20}\:m$

To find: Length of room.

We know that Area of the room = product of the length and breadth

Area = length × breadth

$\frac{153}{10}=length\times2\frac{11}{20}$

$\frac{153}{10}=length\times\frac{51}{20}$

$length=\frac{153}{10}\times\frac{20}{51}$

$length=6\:m$

Therefore, Length of room is 6 m.

Answer 2

Answer:

6 m

Step-by-step explanation:

Area of rectangular room = $153 \div 10 m^2$

Breadth of room =  $2\frac{11}{20}=\frac{51}{20}m^2$

Area of rectangular room = $Length \times Breadth$

So, $153 \div 10=Length \times \frac{51}{20}$

$\frac{\frac{153}{10}}{\frac{51}{20}}=Length$

$6=Length$

So, The length of the room is 6 m