Question

find the length of a second pendulum at a place where g =10m s-1

Answer 1

Time period of seconds pendulum = 2 s

T = 2 π sqrt(L / g)

L = [T^2 g / (2 π)^2]
= [(2^2 * 10) / (2 π)^2]
= 1.0 m

Length of the seconds pendulum is 1.0 m