Question

Find the length of a seconds' pendulum at a place
where g = 10 ms
10 m s-2 (Take n = 3.14).​

Answer 1

Answer:

Explanation:

T=

Solution :

⏭ Given:

✏ Gravitational acceleration = 10m/s

✏ Value of π = 3.14

⏭ To Find:

✏ Length of a second pendulum

⏭ Concept:

✏ We know that, Time period of second pendulum = 2sec

⏭ Formula:

✏ Formula of time period of simple pendulum in terms of length of pendulum and gravitational acceleration is given by...

T=2π√l/9​  ​

T denotes time period

l denotes length of pendulum

g denotes gravitational acceleration

⏭ Calculation:

l=

π  

2

 

g

​  

=  

3.14  

2

 

10

​  

=1.01m