Find the length of a shadow of a tower if height of a tower is 50 feet and Sun's elevation is 60 degree
Answers
Answered by
1
Step-by-step explanation:
LetABbetower
BCbeoriginalshadow.
BDbefinalshadow.
Given
BD−BC=CD=50 m
InΔABC,
tan60
∘
=
CD
AB
⇒
3
AB
=BC−−−−(1)
InΔABD
tan30
o
=
BD
AB
⇒
3
1
=
(BC+CD)
AB
⇒AB
3
=
3
AB
+50from(1)
⇒AB
3
−
3
AB
=50
⇒3AB−
3
AB
=50
∴AB=50×
2
3
=25×1.735
=43.30 m
Which is the required answer.
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Answered by
1
Answer:
given : ht of tower = 50 ft
agl = 60°
to find : shadow
soln :
tan 60° = opposite side/ adjacent side
root 3 = 50 / adj side
adj side = 50/ root 3
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