Question

find the length of a simple pendulum which completes 6 oscillation in 1.8s. take g=9.8m/s*s​

Answer 1

Answer:

The Length is 0.022 m or, 2.2 cm.

Explanation:

g = 9.8 m/s²

No. of oscillations = 6

Time taken for oscillations = 1.8 s

Frequency = 6/1.8 Hz

= 3.33 Hz

Time Period = 1/F

= [1/3.33] s

= 0.3 s

Length of Simple Pendulum = Time Period = 2$\pi$√l/g

= 0.3 = 2*3.14* √l/9.8

= 0.3 = 6.28 * √l/9.8

= 0.3/6.28 = √l/9.8

= (0.3)²/(6.28)² = l/9.8

= [(0.3)² * 9.8] / (6.28)² = l

= [0.09*9.8] / 39.43 = l

= 0.882/39.43 = l

= 0.022 m = l

or,

= 2.2 cm = l

Hope this helps.

Answer 2

Answer:

2.2 cm

Explanation:

g = 9.8 m/s²

No. of oscillations = 6

Time taken for oscillations = 1.8 s

Frequency = 6/1.8 Hz

= 3.33 Hz

Time Period = 1/F

= [1/3.33] s

= 0.3 s

Length of Simple Pendulum = Time Period = 2√l/g

= 0.3 = 2*3.14* √l/9.8

= 0.3 = 6.28 * √l/9.8

= 0.3/6.28 = √l/9.8

= (0.3)²/(6.28)² = l/9.8

= [(0.3)² * 9.8] / (6.28)² = l

= [0.09*9.8] / 39.43 = l

= 0.882/39.43 = l

= 0.022 m = l

or,

= 2.2 cm = l

Hope this helps.