Question

Find the length of a simple pendulum which completes 6 oscillations in 15s. Take g = 98m/s2 and π = 3.14

Answer 1

Answer:

T = 2.5s, L = 1.55m

Explanation:

a pendulum completes 6 oscillations in 15 sec

time period, T = 15/6 = 2.5 s

Let the length of the pendulum = L

we know that:

$T = 2 \pi\sqrt{\frac{L}{g}} \\ \\ \Rightarrow 2.5 = 2 \pi\sqrt{\frac{L}{9.8}}\\ \\ \Rightarrow 2.5 = 6.28 \sqrt{\frac{L}{9.8}}\\ \\ \Rightarrow L={(\frac{2.5}{6.28}) }^{2} \times 9.8 = 1.55m$

Hence time period is 2.5 second and length of pendulum is 1.55 m