Question

Find the length of a simple pendulum whose time period at a place is 1.9 sec and g =
9.8 m/ S^2

Answer 1

Answer:

Time period of a simple pendulum with length L L is given by, T=2πLg−−√ T=2πLg .

When a pendulum ticks second, each swing is of one second duration. So one oscillation is of two second duration or the time period T T is equal to two second.

From the equation of time period we can calculate the length as L=gT24π2 L=gT24π2 .

So, L=9.8×224(3.14)2=0.9939m L=9.8×224(3.14)2=0.9939m .

This is approximately equal to one meter.

This pendulum is called seconds pendulum.

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