Question

Find the length of a simple pendulum whose time
period is 4 seconds.​

Answer 1

Answer:

1548.8cm

Explanation:

$t = \frac{1}{2\pi} \sqrt{ \frac{l}{g} } \: \: or \: \: {t}^{2} = \frac{1}{4 {\pi}^{2} } \frac{l}{g}$

from above

$l = {t}^{2} \times 4 \times {\pi}^{2} \times g \\ \\ = 4 \times 4 \times \frac{22}{7} \times \frac{22}{7} \times 9.8 \\ \\ = 16 \times 22 \times 22 \times \frac{9.8}{7 \times 7} \\ \\ = 16 \times 22 \times 22 \times 0.2 \\ \\ = 1548.8 \: cm$

So this the required length.

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