Question

Find the length of a simple pendulum whose time period is 4 sec. [Take g=π2m/s2g=π2m/s2].​

Answer 1

Answer:

l≈15.9 m

Explanation:

Given: The pendulum takes 4sec to swing in each direction, which means it swings in one side of the pendulum for 4 sec.

So, half time period, T/2= 4s

Time period of simple pendulum, T=2×4=8s

T=2π√l/g

⇒8=2π √l/10

⇒l= 64×10/4×π²

⇒l≈15.9 m