Question

Find the length of a simple pendulum whose time period of oscillation is 1.8 sec at a
place where g = 9.8 m .

Answer 1

Answer:

ANSWER

If T

1

is initial time period and T

2

is the final time period, then

T

1

=T

T

2

=

2

3

T

If L

1

is initial length and L

2

is the final length, then

L

1

=l

L

2

=(l+0.6)

T=2π

g

e

Tα

l

∴

l

1

T

1

=

2

l+0.6

3

4(l+0.6)=9l

5l=2.4

l=0.48m

Answer 2

Answer:

here's your answer

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