Question

find the length of a tangent drawn from a point 10cm away from the center of the circle of radius 6cm

Answer 1

hey mate.....
we know that tangents are perpendicular to the radius of circle.
and according to question..
AB = 6 cm = radius
BC = 10 cm
so....now by Pythagoras theorem
${(ab)}^{2} + ( {ac)}^{2} = {(bc)}^{2} \\ {6}^{2} + {ac}^{2} = {10}^{2} \\ {ac}^{2} = 100 - 36 \\ ac = \sqrt{64} \\ ac = 8cm$
HOPE THIS HELP YOU ☺☺☺.....

Answer 2

Thank you for asking this question:

Here is your answer.

The question has some options too, below are the missing options:

a) √7 cm

b) 2√34 cm

c) 16 cm

d)8 cm

The correct answer is Option D: 8cm

In ΔOPQ, ∠Q = 90°

∴ OP² = OQ² + PQ²

10² = 6² + PQ²

PQ² = 100 - 36

= 64

PQ = 8 cm

If there is any confusion please leave a comment below.