find the length of a tangent drawn from a point 10cm away from the centre of a circle of radius 6cm
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let O be the Centre of the circle
and AB be the tangent and OA be the radius
therefore AB is perpendicular to OA(tangent is perpendicular to the radius)
therefore triangle AOB is a right angled triangle.with OB as it's hypotenuse.
therefore by Pythagoras theorem
in triangle AOB
AB^2+(6)^2=(10)^2
=>AB=√100-36
=>AB=8cm
therefore the length of the tangent is 8cm.
I hope this will help you.
and AB be the tangent and OA be the radius
therefore AB is perpendicular to OA(tangent is perpendicular to the radius)
therefore triangle AOB is a right angled triangle.with OB as it's hypotenuse.
therefore by Pythagoras theorem
in triangle AOB
AB^2+(6)^2=(10)^2
=>AB=√100-36
=>AB=8cm
therefore the length of the tangent is 8cm.
I hope this will help you.
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Thank you for asking this question:
Here is your answer.
The question has some options too, below are the missing options:
a) √7 cm
b) 2√34 cm
c) 16 cm
d)8 cm
The correct answer is Option D: 8cm
In ΔOPQ, ∠Q = 90°
∴ OP² = OQ² + PQ²
10² = 6² + PQ²
PQ² = 100 - 36
= 64
PQ = 8 cm
If there is any confusion please leave a comment below.
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